Centrifugal Pump Power Calculator for Sale

Pump Power Equation:

\[ P = \frac{\rho \times g \times Q \times H}{\eta} \]

Fluid Density (ρ):

kg/m³

Flow Rate (Q):

m³/s

Head (H):

meters

Efficiency (η):

decimal (0-1)

Pump Power (P):

Unit Converter ▲

Unit Converter ▼

From:	To:

1. What is Centrifugal Pump Power?

The power required by a centrifugal pump is the energy needed to move fluid at a specific flow rate against a certain head (pressure), accounting for the pump's efficiency. It's crucial for selecting the right motor size and ensuring energy-efficient operation.

2. How Does the Calculator Work?

The calculator uses the pump power equation:

\[ P = \frac{\rho \times g \times Q \times H}{\eta} \]

Where:

\( P \) — Power (W)
\( \rho \) — Fluid density (kg/m³)
\( g \) — Gravitational acceleration (9.81 m/s²)
\( Q \) — Volumetric flow rate (m³/s)
\( H \) — Head (m)
\( \eta \) — Pump efficiency (0-1)

Explanation: The equation calculates the hydraulic power needed to move the fluid, then divides by pump efficiency to get the actual power requirement.

3. Importance of Pump Power Calculation

Details: Accurate power calculation ensures proper motor sizing, prevents underpowered or overpowered systems, and helps optimize energy consumption in pumping systems.

4. Using the Calculator

Tips:

For water at 20°C, density is approximately 1000 kg/m³
Typical pump efficiencies range from 0.7 to 0.9
Convert flow rates from L/s to m³/s by dividing by 1000
Head is the height the pump can lift the fluid

5. Frequently Asked Questions (FAQ)

Q1: Why is pump efficiency important?
A: Efficiency affects energy consumption and operating costs. Higher efficiency pumps save energy but may cost more initially.

Q2: How does fluid density affect power requirements?
A: Denser fluids require more power to pump at the same flow rate and head. Power is directly proportional to density.

Q3: What's the difference between hydraulic power and shaft power?
A: Hydraulic power is the theoretical power needed to move the fluid. Shaft power (calculated here) includes pump inefficiencies.

Q4: How do I account for system losses?
A: System losses (pipe friction, fittings) should be added to the static head before calculation, or use a lower efficiency value.

Q5: Can this be used for other pump types?
A: The basic equation applies to all pumps, but specific efficiency values may differ for positive displacement pumps.